再分享一个通达信超金钻公式,最多留三天,源码

源码

{CX1:=OMA(C,5) AND C>MA(C,10) AND C>MA(C,20);
CX11:=OMA(C,5) AND C>MA(C,10) AND C>MA(C,30);
CX2:=MA(C,5)>MA(C,10) AND MA(C,10)>MA(C,20) AND MA(C,10)>MA(C,30) AND MA(C,30)>MA(C,60);
CX3:=NOT(CROSS(MA(C,10),MA(C,5)) OR CROSS(MA(C,30),MA(C,20)));
CX4:=C>O AND C/REF(C,1)>1.02;
CXG:(CX1 OR CX11) AND CX2 AND CX3 AND CX4;}
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LCX1:=OMA(C,5) AND C>MA(C,10) AND C>MA(C,20);
LCX11:=OMA(C,5) AND C>MA(C,10) AND C>MA(C,30);
LCX2:=MA(C,5)>MA(C,10) AND MA(C,10)>MA(C,20) AND MA(C,10)>MA(C,30) AND MA(C,30)>MA(C,60);
LCX3:=NOT(CROSS(MA(C,10),MA(C,5)) OR CROSS(MA(C,30),MA(C,20)) OR CROSS(MA(C,50),MA(C,10))
OR CROSS(MA(C,10),MA(C,20)) OR CROSS(MA(C,10),MA(C,30)));
LCX4:=C>O AND C/REF(C,1)>1.02;
LCXG:(LCX1 OR LCX11) AND LCX2 AND LCX3 AND LCX4;