MA7:=MAX(MA5,MAX(MA10,MAX(MA22,MAX(MA60,MA120)))); MA8:=MIN(MA5,MIN(MA10,MIN(MA22,MIN(MA60,MA120)))); 连续收阴:=EVERY(OPEN CLOSE,3); 今日阳:=C O AND C/REF(C,1) 1.03; XG:MA7/MA8 1.2 AND CROSS(KDJ.J,0) AND REF(连续收阴,1) AND 今日阳 ;