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  • 百发百中解套(指标/源码、主图、通达信)基础知识科普、嵌套多条件语句分解

    正文概述    2024-04-13 14:00:50  

    百发百中解套(指标/源码、主图、通达信)基础知识科普、嵌套多条件语句分解

    QUAN:(CLOSE-DMA(CLOSE,VOL/SUM(VOL,13)))/DMA(CLOSE,VOL/SUM(VOL,13))*100 =-28 AND (CLOSE-DMA(CLOSE,VOL/SUM(VOL,34)))/DMA(CLOSE,VOL/SUM(VOL,34))*100 =-19
    AND C/REF(C,25) =1.1 AND IF((((HIGH (LOW * 1.051)) AND (COUNT((HIGH (LOW * 1.051)),5) 1)) AND ((((CLOSE / MA(CLOSE,40)) * 100) 78) OR
    (((CLOSE / MA(CLOSE,60)) * 100) 74))),2,0) AND
    (SMA(MAX(C-REF(C,2),0),7,1)/SMA(ABS(C-REF(C,2)),7,1)*100) 15 AND IF(SMA((CLOSE-LLV(LOW,8))/(HHV(HIGH,8)-LLV(LOW,8))*100,2,1) REF(SMA((CLOSE-LLV(LOW,8))/(HHV(HIGH,8)-LLV(LOW,8))*100,2,1),1)
    AND REF(SMA((CLOSE-LLV(LOW,8))/
    (HHV(HIGH,8)-LLV(LOW,8))*100,2,1),1) REF(SMA((CLOSE-LLV(LOW,8))/(HHV(HIGH,8)-LLV(LOW,8))*100,2,1),2)
    AND SMA((CLOSE-LLV(LOW,8))/(HHV(HIGH,8)-LLV(LOW,8))*100,2,1) 23 ,1.5,0) AND FILTER((C/MA(C,48)) 0.75 AND (C/MA(C,70)) 0.70 AND
    ((C-L)/C 0.02 OR C REF(C,1)*1.01) AND V REF(V,1)*2.8 AND (COUNT(C O*0.93,2)=2 OR COUNT(H/L 1.1,5) 3),3);
    {DRAWTEXT(QUAN,88,'弱市百发百中'),COLORFFFF00;};

    百发百中解套(指标/源码、主图、通达信)基础知识科普、嵌套多条件语句分解

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