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  • 通达信寻找快牛系列——突破排序 源码分享 附图

    正文概述    2024-04-14 20:05:43  
    {4突破排序}
    {TY:=C;
    HD:=FILTER(BACKSET(FILTER(REF(TY,10)=HHV(TY,2*10+1),10),10+1),10);
    LD:=FILTER(BACKSET(FILTER(REF(TY,10)=LLV(TY,2*10+1),10),10+1),10);
    A:=REF(C,BARSLAST(HD));
    B:=REF(C,BARSLAST(LD));
    T1:=BARSLAST(HD)T2:=BARSLAST(HD)>BARSLAST(LD) AND NOT(LD);
    顶:=IF(T1,A,A),COLORYELLOW,LINETHICK1;}

    Z:=EMA(EMA(C,1),5),COLOR00FFFF,LINETHICK3;
    BB:=EMA(HHV(Z,5),1),COLORMAGENTA,LINETHICK3;
    J:=EMA(HHV(BB,21),1),COLOR0089FF,LINETHICK2;
    W:=EMA(HHV(J,21),2),COLORDB89FF,COLOR00FF00,LINETHICK2;
    T:=EMA(HHV(W,21),3),COLOR8916FF,LINETHICK2;
    S:=EMA(HHV(T,21),4),COLORFFCC62,LINETHICK2;
    JJ:=EMA(HHV(S,21),5),COLORFF9D52,LINETHICK2;
    M:=EMA(HHV(JJ,21),6),COLORFF5B5E,LINETHICK2;

    M1:=(-( HHV(EMA(C,5),14)-C)/C*5000);
    M2:=(CLOSE+LOW+3*OPEN+HIGH)/6;
    M3:=(20*M2+19*REF(M2,1)+18*REF(M2,2)+17*REF(M2,3)+16*REF(M2,4)+15*REF(M2,5)+14*REF(M2,6)+13*REF(M2,7)
    +12*REF(M2,8)+11*REF(M2,9)+10*REF(M2,10)+9*REF(M2,11)+8*REF(M2,12)+7*REF(M2,13)+6*REF(M2,14)
    +5*REF(M2,15)+4*REF(M2,16)+3*REF(M2,17)+2*REF(M2,18)+REF(M2,20))/210;
    M4:=MA(M3,6);
    M5:=(M3-M4)*1.2;
    M6:=(O*2+H+L)/4*10;
    M7:=EMA(M6,6)-EMA(M6,55);
    M8:=EMA(M7,6);
    M9:=(M7-M8)*0.06;
    M10:=M5+M9;
    M11:=M10>0;
    M12:=MA(O,3),COLORRED,LINETHICK;
    M13:=MA(O,13),COLORRED,LINETHICK;
    M14:=MA(O,34),COLORRED,LINETHICK;
    M15:=M12>=M13 AND M14>=REF(M14,1);
    M16:=EMA(O,12);
    M17:=EMA(O,50);
    M18:=M16-M17>0;
    M19:=C/REF(C,1)-1;
    M20:=IF(M15,2,0)+IF(M11,2,0)+IF(M18,2,0)+M19;
    M21:=(M20/10+M1/1000)*100+25,COLORWHITE;
    ZF:=C/REF(C,1)*100-100;
    突破排序:IF(CROSS(C,M) {AND CROSS(C,顶)},ZF,0);

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